Answer:
2p+3
Explanation:
\frac{2{p}^{2}+9p+9}{p+3}
p+3
2p
2
+9p+9
(2p2 + 9p + 9)/(p + 3)
1) Split the second term in 2{p}^{2}+9p+92p
2
+9p+9 into two terms.
\frac{2{p}^{2}+6p+3p+9}{p+3}
p+3
2p
2
+6p+3p+9
2 )Factor out common terms in the first two terms, then in the last two terms.
\frac{2p(p+3)+3(p+3)}{p+3}
p+3
2p(p+3)+3(p+3)
3) Factor out the common term p+3p+3.
\frac{(p+3)(2p+3)}{p+3}
p+3
(p+3)(2p+3)
4) Cancel p+3p+3.
2p+3
2p+3