Answer:
YES, it is possible to solve a quadratic equation that is not factorable over the set of integers.
Explanation:
A quadratic equation is a condition of the second degree, which means it contains no less than one term that is squared. The standard frame is
ax² + bx + c = 0
with a, b, and c being constants or numerical coefficients, and x is an obscure variable.
The quadratic equation includes just a single obscure, it is designated "univariate". Specifically, it is a second-degree polynomial condition, since the best power is two.
Whenever factorization fails you can use:
a) completing the square method
b) quadratic formula
to solve the quadratic equation.
The answers can lead you to the complex numbers but there is always a solution.