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Two consecutive angles in a parallelogram have the measures x+5 and 4x-10. Find the smaller angle.
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Two consecutive angles in a parallelogram have the measures x+5 and 4x-10. Find the smaller angle.

User Gerardo Pardo
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1 Answer

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If angles are consecutive then Their sum will be 180°.

So,
x+5+(4x-10) = 180
5x-5 = 180
5(x-1) = 180
x-1 = 36
x = 37

Angles are x+5 that is 37+5 = 42°
and 2nd one is 4x-10 that is 4x37-10 = 138°

Smaller Angle Is 42°
User Zhi
by
5.7k points
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