Final answer:
To calculate the mass of sodium chloride formed, we need to calculate the moles of sodium carbonate, determine the stoichiometry of the reaction, and then convert the moles of sodium chloride to grams.
Step-by-step explanation:
To find the mass of sodium chloride formed when 7.5 g of sodium carbonate reacts with hydrochloric acid, we need to calculate the moles of sodium carbonate, determine the stoichiometry of the reaction, and then convert the moles of sodium chloride to grams.
Step 1: Calculate the moles of sodium carbonate (Na2CO3)
Number of moles = mass / molar mass
Number of moles = 7.5 g / 105.99 g/mol (molar mass of Na2CO3)
Number of moles = 0.0707 mol
Step 2: Determine the stoichiometry of the reaction
From the balanced equation: 1 mol Na2CO3 reacts with 2 mol HCl to form 2 mol NaCl
So, 0.0707 mol Na2CO3 will react with 2 * 0.0707 mol HCl to form 2 * 0.0707 mol NaCl
Step 3: Convert moles of NaCl to grams
Mass of NaCl = moles * molar mass
Mass of NaCl = 2 * 0.0707 mol * 58.44 g/mol (molar mass of NaCl)
Mass of NaCl = 8.3 g
The mass of sodium chloride formed when 7.5 g of sodium carbonate reacts with hydrochloric acid is 8.3 grams.