Question

A former high school teacher was discovered making meth, and the dea recently analyzed some confiscated material from a drug bust he was associated with. they found a compound with the empirical formula c17h14o7 that has a molar mass of 990.87 g/mol. what is the value of n (the multiplier) necessary to find the molecular formula?

Answer 1

n = 3. (I know I'm answering this a week later, still hope this helps you understand the concept.) C17H14O7 has a molar mass of 330.29 g/mol. An empirical formula is essentially just a chemical formula simplified down to it's most common denominator of the subscripts. Dividing 990.87 g/mol by 330.29 g/mol gives us 3, the value of n. To go further, the chemical he was using was C51H42O21, or... (2R,2'R,2''R,3R,3'R,3''R,4R,4'R,4''S)-2,2',2''-Tris(3,4-dihydroxyphenyl)-4''-(2,4,6-trihydroxyphenyl)-3,3',3'',4,4',4''-hexahydro-2H,2'H,2''H-4,8':4',8''-terchromene-3,3',3'',5,5',5'',7,7',7''-nonol, whatever the hell that is.

Answer 2

3 is the value of n necessary to find the molecular formula.

Step-by-step explanation:

The equation used to calculate the valency is :

`n=\frac{\text{molecular mass}}{\text{empirical mass}}`

We are given:

Mass of molecular formula = 990.87 g/mol

Mass of empirical formula of
`C_(17)H_(14)O_7`:

`12 g/mol+17+1 g/mol* 14+16 g/mol* 7=330 g/mol`

Putting values in above equation, we get:

`n=(990.87 g/mol)/(330 g/mol)=3.00`

3 is the value of n necessary to find the molecular formula.

The molecular formula is :
`C_(51)H_(42)O_(21)`