Question

Karim read the book in 3 days. during the first day he read 1 5 of the book. during the second day he read 5 8 of what was left. on the third day he read 1 3 of the rest of the book and last 16 pages. how many pages was in the book?

Answer 1

80

Step-by-step explanation:

Let the total number of pages in the book be y. The number of pages read each day is only a fraction of the number of pages in the book. Given that during the first day he read 1 /5 of the book, it means that what is left

= y - 1/5y

= 4/5 y pages

during the second day he read 5 8 of what was left, it means that what is left

= 4y/5 - (4y/5 * 5/8)

=4y/5 - y/2

= 3y/10 pages

If on the third day he read 1 3 of the rest of the book and last 16 pages, what is left after he read 1/3 of what was left from the second day

=3y/10 - (1/3 * 3y/10)

= 3y/10 - y/10

= y/5

This is equivalent to the last 16 pages

y/5 = 16

y = 16 * 5

= 80 pages

Answer 2

ANSWER:

There were 80 pages in the book.

Step-by-step explanation:

Step-by-step explanation:

let,

total pages =x

on day 1 pages read =1/5*x .

so pages left were = 1-1/5*x

left pages =4/5*x.

on day 2 pages read=5/8 of left pages

so,

5/8*4/5*x = 1/2*x

so far total read pages = 1/5*x+1/2*x =7/10*x.

and pages left are = 1-7/10*x = 3/10*x.

then,

pages read on day 3 are =1/3 * 3/10 * x +16

but pages left and pages read on last day are equal so,

3/10*x = 1/3 *3/10 *x +16

solving this gives,

3/10*x = 1/10 *x +16

1/5* x = 16

x= 80

as we know x= total pages

so,total pages =80