Answer:
hello your question is incomplete below is the complete question
Suppose that there are two components A and B, in a mixture. The chemical affinity of A for the stationary phase is less than that of B and the chemical affinity of A for the mobile phase is greater than that of B. If the mixture is subject to paper chromatography
answer : 5.751 cm
Step-by-step explanation:
lets make an assumption that the RF value of A = 0.71
therefore when a solvent travels 8.1 cm with such conditions
The distance travelled by a spot containing the same substance
= Rf . 8.1 cm
= 0.71 * 8.1 = 5.751 cm