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Consider the following reaction:

N2(g) + 3H2(g) 2NH3(g)

Determine the standard free energy of the the reaction at298K?

User Mthierba
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7.2k points

1 Answer

1 vote

Given reaction:

N2(g) + 3H2(g) → 2NH3(g)

The standard free energy change is given as:

ΔG° = ∑ nΔGf(products) - ∑ nΔGf(reactants)

= [2ΔGf(NH3(g))] - [ΔGf(N2(g)) + 3ΔGf(H2(g))]

= [2(-16.48)] - [ 1(0) + 3(0)] = -32.96 kJ

Ans: Free energy of the reaction is -32.96 kJ, i.e. reaction is spontaneous.

User Damodar P
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9.6k points
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