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He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→li(s) −3.04 cl2(g)+2e−→2cl−(aq) +1.36 in a galvanic cell, the two half-reactions combine to 2li(s)+cl2(g)→2li+(aq)+2cl−(aq) calculate the cell potential of this reaction under standard reaction conditions. express your answer with the appropriate units.

User Topofsteel
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2 Li(s) +Cl₂→ 2 Li⁺ (aq) + 2Cl⁻ (aq)

The cell potential of the reaction above is +4.40V

calculation

Cell potential =∈° red - ∈° oxidation

in reaction above Li is oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04

Cl is reduce from oxidation state 0 to -1 therefore the ∈°red = +1.36 V

cell potential is therefore = +1.36 v -- 3.04 = + 4.40 V

User Labratmatt
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