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One leg of a right triangle is 2cm longer than the other leg. The hypotenuse is 10cm long. Determine the length of the shorter leg.​

User Xenocyon
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1 Answer

28 votes
28 votes

Answer:

shorter leg = 6 cm

Explanation:

let n be the shorter leg then n + 2 is the longer leg.

using Pythagoras' identity in the right triangle

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

n² + (n + 2)² = 10² , that is

n² + n² + 4n + 4 = 100

2n² + 4n + 4 = 100 ( subtract 100 from both sides )

2n² + 4n - 96 = 0 ( divide through by 2 )

n² + 2n - 48 = 0 ← in standard form

(n + 8)(n - 6) = 0 ← in factored form

equate each factor to zero and solve for n

n + 8 = 0 ⇒ n = - 8

n - 6 = 0 ⇒ n = 6

However , n > 0 then n = 6

the shorter leg is 6 cm long

User Lynx
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