Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

Question

asked Dec 5, 2019 61.0k views

1 Answer

Trnelson · Answer 1 · 2019-12-09T12:31:48+0000

Answer:

-13

Explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term = 5th term + 4(-8)

= 19 - 32

= -13 (answer