Question

Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

Answer 1

-13

Explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term = 5th term + 4(-8)

= 19 - 32

= -13 (answer