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Trigonometry help- double angle formulae

Trigonometry help- double angle formulae-example-1
User Luizfzs
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1 Answer

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Explanation:

We have sinA = 4/5 and sinB = 7/25.

=> cosA = sqrt(1 - sin²A) = 3/5

=> cosB = sqrt(1 - sin²B) = 24/25

P.S. Cosine must be positive in Quadrant I.

sin(A - B)

= sinAcosB - cosAsinB

= (4/5)(24/25) - (3/5)(7/25)

= 75/125 = 3/5. (Shown)

User Kasaku
by
7.3k points

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