Question

4^4x-5= 8^3x-4 solve

Answer 1

`4^(4x-5)=8^(3x-4)\\\\(2^2)^(4x-5)=(2^3)^(3x-4)\qquad\text{use}\ (a^n)^m=a^(nm)\\\\2^(2(4x-5))=2^(3(3x-4))\iff2(4x-5)=3(3x-4)\qquad\text{use distributive property}\\\\(2)(4x)+(2)(-5)=(3)(3x)+(3)(-4)\\\\8x-10=9x-12\qquad\text{add 10 to both sides}\\\\8x=9x-2\qquad\text{subtract 9x from both sides}\\\\-x=-2\to \boxed{x=2}`