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What is the equation of the line that pases through (2,-6) and has the slope of -1

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\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies -1 \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=-1(x-2) \\\\\\ y+6=-x+2\implies y=-x-4

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