Question

Writ an equation of the line perpendicular to y+1=5/3(x+5) through the point (-6,-10

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Answer 1

y+1 = 5/3 (x+5)

y+1 = 5/3x + 83/10

-1 -1

y= 5/3x + 73/10

since it is perpendicular you need to flip the fraction

y-yV1=m(x-xV1)

y+10=-3/5 (x+6)

destribute -3/5 to parenthesies

y+10 = -3/5x - 3 3/5

-10 -10

y= -3/5x - 13 3/5

Answer 2

y +10 = (-3/5)(x +6)

Explanation:

The slope of the given line can be read from its point-slope form as 5/3. The slope of a perpendicular line will be the opposite of the reciprocal of that, so will be -1/(5/3) = -3/5.

Using your given point in the point-slope form of the equation of a line, your equation is ...

... y -(-10) = (-3/5)(x -(-6))

... y + 10 = (-3/5)(x +6) . . . . . simplified