Question

Identify the nuclide that would be formed from the alpha particle emission of Fm-257.

identify the nuclide that would be formed from the beta particle emission of Cf-253.

PLZ HELP!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Answer: 1) The nuclide formed from the alpha decay of
`_(100)^(257)\textrm{Fm}` is
`_(98)^(253)\textrm{Cf}`

2) The nuclide formed from the beta-minus decay of
`_(98)^(253)\textrm{Cf}` is
`_(99)^(253)\textrm{Es}`

Explanation:

1) For alpha-decay

In this process, alpha particle is released.

Equation follows:

`_(100)^(257)\textrm{Fm}\rightarrow _(98)^(253)\textrm{Cf}+_2^4\alpha`

The nuclide formed is
`_(98)^(253)\textrm{Cf}`

2) For beta-minus decay

In this process, a neutron is converted into a proton and an electron.

Equation follows:

`_(98)^(253)\textrm{Cf}\rightarrow _(99)^(253)\textrm{Es}+_(-1)^0\beta`

The nuclide formed is
`_(99)^(253)\textrm{Es}`