180k views
0 votes
What is the solution to the equation x2 +6x=40

User Kyore
by
8.3k points

2 Answers

3 votes

x² + 6x = 40 Subtract 40 on both sides to get the equation equal to 0.

x² + 6x - 40 = 0

Now you need to factor the equation. To do so, you find the factors of 40 that add or subtract to 6.

Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40

[1 × 40, 2 × 20, 4 × 10, 5 × 8]

4 and 10 subtracts to 6.


Instead of 6x:

x² + 6x - 40 = 0


You can replace 6x with:

x² - 4x + 10x - 40 = 0 [this is because the sum of -4x and 10x is 6x]


Now factor the equation separately. Factor out x in (x² - 4x), and factor out 10 in (10x - 40)

x(x - 4) + 10(x - 4) = 0 Factor out (x - 4)

(x - 4)(x + 10) = 0


x - 4 = 0 Add 4 on both sides

x = 4


x + 10 = 0 Subtract 10 on both sides

x = -10


x = 4, x = -10

User Scones
by
8.5k points
4 votes

Answer:

x=10 x=-4

Explanation:

x^2 +6x = 40

subtract 40 from each side

x^2 +6x -40 = 0

what numbers multiply to -40 and add to 6

-10 *4 = -40 -10 +4 = 6


(x-10) (x+4) = 0

using the zero product property

x-10 = 0 x+4 =0

x=10 x=-4


User Strkol
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories