Question

An air pump does 5,600 J of work to launch a water bottle rocket into the air. If the air pump applies 150 N of force to the rocket at an angle of 45° to the ground, what is the horizontal distance the water bottle rocket travels? Round your answer to two significant figures.

Answer 1

5.3 × 10^1 m

Step-by-step explanation:

Answer 2

Answer: 53 m

Step-by-step explanation:

Work = Force × Displacement

W= F s cosΘ

Where, s is the displacement and F is the force. Θ is the angle between force and displacement

F cosθ is the component of force acting in the horizontal direction.

The air pump applies F = 150 N force at an angle Θ = 45°

W = 5600 J

⇒s = W/F cosθ

`\Rightarrow s =(5600 J)/(150* cos 45^o)\approx 53 m`

Thus, the horizontal distance the water bottle rocket travels is 53 m