95.9k views
3 votes
If you have 4.9 x 10^24 molecules of O2 at STP, how many liters of O2 do you have?

1 Answer

4 votes

Given:

Molecules of O2 at STP = 4.9 * 10²⁴

STP conditions implies-

Temperature T = 273 K

Pressure = 1 atm

To determine:

The volume (V) of O2

Step-by-step explanation:

Based on the ideal gas equation:

PV = nRT-----(1)

where n = number of moles of O2

R = gas constant = 0.0821 L.atm/mol-K

Now, 1 mole of O2 corresponds to 6.023*10²³ molecules

# moles of O2 corresponding to the given molecules=

= 4.9*10²⁴ molecules O2 * 1 mole O2/6.023*10²³ molecules = 8.135 moles

From equation(1) we have:

V=nRT/P = 8.135*0.0821*273/1 = 182.3 L

Ans: Volume of O2 under the given conditions is 182.3 L


User Mogoh
by
8.0k points

No related questions found