Question

Calculate the ratio of effusion rates for helium and argon.

Answer 1

The ratio of effusion rates for helium and argon can be calculated using Graham's law and the square roots of their molar masses.

Step-by-step explanation:

The ratio of the rates of effusion for two gases is inversely proportional to the ratio of the square roots of their molar masses. This relationship is known as Graham's law.

To calculate the ratio of effusion rates for helium and argon, we can use Graham's law. The molar mass of helium is 4.00 g/mol, and the molar mass of argon is 39.95 g/mol. Taking the square roots of these molar masses gives us √4.00 = 2.00 and √39.95 = 6.32, respectively.

Therefore, the ratio of the effusion rates of helium to argon is 2.00/6.32, which simplifies to approximately 0.32.

Answer 2

Answer : The ratio of effusion rates for helium and argon is 3.2 : 1

Solution : Given,

Molar mass of Helium = 4 g/mole

Molar mass of Argon = 40 g/mole

Rate of effusion : It is defined as the rate of effusion of a gas is inversely proportional to the square root of the molar mass of the gas.

Formula used :

`\text{Rate of effusion}=(1)/(√(M))`

where, M is the molar mass.

`(Rate_(He))/(Rate_(Ar))=\sqrt{(M_(Ar))/(M_(He))}`

Now put all the given values in this expression, we get

`(Rate_(He))/(Rate_(Ar))=\sqrt{(40)/(4)}=(3.2)/(1)`

Therefore, the ratio of effusion rates for helium and argon is 3.2 : 1