Question

Write an equation in point-slope form and in slope-intercept form.

Answer 1

The point-slope form:

`y-y_1=m(x-x_1)`

The slope-intercept form:

`y=mx+b`

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the points (1, -5) and (-3, -7). Substitute:

`m=(7-(-5))/(-3-1)=(12)/(-4)=-3\\\\y-(-7)=-3(x-(-3))\\\\\boxed{y+7=-3(x+3)}`

Rewrite to the slope-intercept form:

`y+7=-3(x+3)` use distributive property

`y+7=-3x-9` subtract 7 from both sides

`\boxed{y=-3x-16}`