1) 1.08 m/s^2
Step-by-step explanation:
Acceleration is equal to the change in velocity divided by the time taken:

where
v is the final velocity
u is the initial velocity
is the time taken
In this problem, we have:
- initial velocity: u = 0 (you start from rest)
- final velocity: v = 5.4 m/s
- time taken:

Therefore, the acceleration is

2) -0.54 m/s^2
We can calculate the acceleration to slow down using the same formula as before, but this time the data are as follows:
- initial velocity : u = 5.4 m/s
- final velocity : v = 0 (you come to a stop)
- time taken :

using the same formula, we find

And the negative sign means it is a deceleration.