Answer: 1.35 kg m/s
Step-by-step explanation:
The law of conservation of momentum states that the total momentum before and after the collision is conserved, therefore:
![p_i=p_f](https://img.qammunity.org/2019/formulas/physics/middle-school/ey9ad2q50vu6hve6i9yy0yprgzng73keu0.png)
we can calculate the total momentum before the collision,
, since we know the masses and the initial velocities of the two balls.
The momentum along the x-axis is given only by the first ball, since the second one is moving on the y-axis:
![p_x = m v_1 = (0.50 kg)(1.8 m/s)=0.9 kg m/s](https://img.qammunity.org/2019/formulas/physics/middle-school/jvoe772b90uako1uklgcl1jjw9ufgb2xvy.png)
The momentum along the y-axis is given only by the second ball, since the first one is moving on the x-axis:
![p_y = m v_2 = (0.50 kg)(2.0 m/s)=1.0 kg m/s](https://img.qammunity.org/2019/formulas/physics/middle-school/2a18jb9352cogimrq7hg2tntwl5i6kukk0.png)
So, the magnitude of the resultant momentum is
![p_i=√(p_x^2 +p_y^2)=√((0.9 kg m/s)^2+(1.0 kg m/s)^2)=1.35 kg m/s](https://img.qammunity.org/2019/formulas/physics/middle-school/d2vgm8gukkivjfw50i8xdal56429gjs61d.png)
And since the total momentum after the collision is equal to the momentum before the collision,
![p_f = 1.35 kg m/s](https://img.qammunity.org/2019/formulas/physics/middle-school/uky32jyqjh7wjehptf69y1q1qwy3z2qyng.png)