Question

The drawing shows Robin Hood (mass = 83.4 kg) about to escape from a dangerous situation. With one hand, he is gripping the rope that holds up a chandelier (mass = 243.0 kg). When he cuts the rope where it is tied to the floor, the chandelier will fall, and he will be pulled up toward a balcony above. Ignore the friction between the rope and the beams over which it slides, and find:

a. the acceleration with which Robin is pulled upward.
b. the tension in the rope while Robin escapes.

Answer 1

`a=4.797791411m/s^2\\a\approx4.8m/s^2`

`T=1217.64N`

Step-by-step explanation:

From the question we are told that

Mass of Robin
`M_R=83.4kg`

Mass of chandelier
`M_c= 243.0 kg`

a)Generally the equation for acceleration in system is mathematically given by

`a=(m_2-m_1)/(m_1+m_2) g`

`a=(243.0-83.4)/(243.0+83.4) *9.8`

`a=(159.6)/(326) *9.8`

`a=(1564.08)/(326)`

`a=4.797791411m/s^2\\a\approx4.8m/s^2`

b)Generally the equation for Tension is given mathematically as

`T=m_1a+m_1g`

`T=83.4(4.8+9.8)`

`T=1217.64N`