Answer:
Find the probability that n = 6 runs result in Y1=3,Y2=1, and Y3=2
=0.823
Explanation:
Multinomial distribution
p(y1;y2,y3…..yk) = (n!/y1!,y2!,y3!…y4!) x p1^y1 x p2^y2 x p3^y3 x pk^yk)
The rat chooses of the three exists at random:
p = 1/3
p(3,2,1) = 6! / 3! 1! 2! (1/3)^3 (1/3)^1 (1/3)^2
=20/243
=0.823