Answer:
The probability that he or she orders either a pizza or salad is 80%.
Explanation:
Given : At a pizza shop, 75% of the customers order pizza, 20% of the customers order salad, and 15% of the customers order a pizza and a salad. If a costumer isn’t chosen at random.
To find : What is the probability that he or she orders either a pizza or salad?
Solution :
Let A be the event that customer order Pizza
Let B be the event that customer order Salad
75% of the customers order pizza,
P(A)=75%=0.75
20% of the customers order salad,
P(B)=20%=0.20
15% of the customers order a pizza and a salad,

Now, The probability that he or she orders either a pizza or salad




Therefore, The probability that he or she orders either a pizza or salad is 80%.