Question

1. Determine the equation (and draw the graph) of the line with slope of 3/2 that passes through the

point (-2, 2).
2. Write (and graph) the equation of the line perpendicular to #1 that goes through the point (-7, 1).
3. Write (and graph) the equation of the line with a slope of ¼ that goes through the point (1, 3).
4. Write (and graph) the equation of the line with a slope of -2 and a y-intercept of 5.
5. Write (and graph) the equation of the line perpendicular to #4 that goes through the point (-2, -2).

Please help guys!! :/

Answer 1

For #1, the equation of the line would be y = 3/2x + 5

Explanation:

The steps you need to follow to solve all of these is to first take the slope and the point and place them into point slope form. The form is below.

y - y1 = m(x - x1)

So we put the slope in for m and the point's coordinates in for x1 and y1.

y - 2 = 3/2(x - -2)

Now we solve for y.

y - 2 = 3/2(x - -2)

y - 2 = 3/2(x + 2)

y - 2 = 3/2x + 3

y = 3/2x + 5

For each of the others of these, you can follow these same steps and get the final answers.