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if the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg*m/s and its mass is 7500 kg what is its speed

User Nafi
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2 Answers

4 votes

speed equal distance divided by time that should help


User Bonzay
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Answer:

Velocity of the space velocity, v = 50,000 m/s

Step-by-step explanation:

It is given that,

The momentum of the NASA space shuttle as it leaves the atmosphere is,
p=3.75* 10^8\ kgm/s

Mass of the space shuttle, m = 7500 kg

We need to find the speed of the NASA space. The momentum of an object is given by the product of mass of the object and its velocity.

p = mv


v=(p)/(m)


v=(3.75* 10^8\ kgm/s)/(7500\ kg)

v = 50,000 m/s

So, the speed of the NASA space shuttle is 50,000 m/s. Hence, this is the required solution.

User Murolem
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