Question

For the following system of equations, what is the x-value of the solution? -x+2=6 6y=x+18

A- -18
B- 0
C- -6
D- 3

Answer 1

For those of you doing unit 7 lesson 2 solving systems using substitution questions 1-4

Explanation:

1. A

2. C

3. C

4. D

Answer 2

Option B is correct.

The value of x is, 0

Explanation:

Given the system of equation:

-x+2y =6 .....[1]

6y =x+18 ......[2]

We can write equation [1] as;

-x = 6-2y or

x = -6 + 2y ......[3]

Substitute equation [3] in [2] we get;

6y =-6 + 2y + 18

or

6y = 2y +12

Subtract 2y from both sides we get;

6y -2y = 2y+ 12 -2y

Simplify:

4y = 12

Divide both sides by 4 we get;

`(4y)/(4) =(12)/(4)`

Simplify:

y =3

Substitute the value of y in equation [3] to solve for x;

x = -6 + 2(3)

x = -6 +6 = 0

Therefore, the value of x is, 0