Question

Given y = (2x + 3)2 Identify the values of a, b, and c.

Answer 1

`a=4,b=12,c=9`

Explanation:

We must first expand, and then compare to the general quadratic form,

`y=ax^2+bx+c`

The given function is

`y=(2x+3)^2`

We rewrite to obtain,

`y=(2x+3)(2x+3)`

This implies that,

`y=2x(2x+3)+3(2x+3)`

We expand to obtain,

`y=4x^2+6x+6x+9`

We simplify to get,

`y=4x^2+12x+9`

Therefore the values are

`a=4,b=12,c=9`