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A scientist mixes 78 grams of potassium with 71 grams of chlorine gas. How much potassium chloride can the scientist expect to be produced?



User Nicolas Cadilhac
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2 Answers

17 votes
17 votes

Final answer:

The question involves using stoichiometry to calculate the amount of potassium chloride that can be produced from a given amount of potassium and chlorine gas. The answer requires determining the limiting reactant and then calculating the theoretical yield based on the balanced chemical equation and molar masses of the reactants.

Step-by-step explanation:

The question is about stoichiometry, the part of chemistry that involves the calculation of the quantities of reactants and products in chemical reactions. Specifically, the question is asking how much potassium chloride (KCl) can be produced from mixing 78 grams of potassium (K) with 71 grams of chlorine gas (Cl2).

To solve this, we need to use the chemical equation for the reaction, which is:
2K + Cl2 → 2KCl

By using the molar masses of potassium (39.0983 g/mol) and chlorine (35.453 g/mol for each atom, but since we're dealing with Cl2, it's 70.906 g/mol for the molecule), we can determine the limiting reactant and then calculate the theoretical yield of potassium chloride.

Since the stoichiometry of the reaction is a 2:1 ratio, we expect two moles of potassium to react with one mole of chlorine gas, forming two moles of potassium chloride for every mole of chlorine gas reacted.

User Justasm
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2.7k points
8 votes
8 votes

Answer:

149 grams

Step-by-step explanation:

in order to do this question, first convert grams into moles.
78 grams of potassium equals 2 moles of potassium
71 grams of chlorine is equal to 2 moles of Cl
Since potassium and Cl react in a 1:1 molar ratio, we would have no limiting reagent in this reaction, and 2 moles of KCl are produced.
2 moles of KCl corresponds to 149 grams.

User Jason Nordwick
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