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the point slope form of the equation of thr line that passes through (-4,-3) and (12,1) and y-1=1/4(x-12). what is the standard form of the equation for this line

2 Answers

3 votes

Answer:

The equation of the line is -x + 4y = -8

Explanation:

To find the equation of this line, we first need to find the slope. To do that, we use the slope equation.

m(slope) = (y2 - y1)/(x2 - x1)

m = (1 - -3)/(12 - -4)

m = (1 + 3)/(12 + 4)

m = 4/16

m = 1/4

Now that we have the slope, we can use it and either point in point-slope form and solve for the standard form of the equation.

y - y1 = m(x - x1)

y - 1 = 1/4(x - 12)

y - 1 = 1/4x - 3

-1/4x + y - 1 = -3

-1/4x + y = -2

-x + 4y = -8

User Cosmin Prund
by
8.5k points
1 vote

Answer:

The answer is the 3rd graph

Explanation:

I did it on edge

User DineshNS
by
8.4k points

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