Ok so we need to set the bottom to 0 to find the vertical asympyotes. This becomes x^2 - 4 = 0. Since we're talking about asymptotes, i'll assume you can solve basic equations. Solving for x and you get x = ±2. This means the vertical asymptotes are at ±2. To solve for horizontal asymptotes you take the limit as x goes to ±∞. Either way you end up with ±∞/∞. Now this isn't 1 because they grow at different rates. You differentiate both the top and bottom(L'hopital) and you get 6x/2x which becomes 3. This means the horizontal asymptote is at y = 3.