Answer:
a = 2
b = 4
c = 8
Explanation:
Remember the relationship:

First, in "a" we have:
a)
![8^(1/3) = \sqrt[3]{8} = 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/udgbrajc4nghom4wapr3aqmra9og45j6d0.png)
then in the next ones, we can use the result that we obtained in the part a:
b)

Now we can do exactly the same in c:
c) where first we need to know that:
2*2*2*2 = 4*4 = 16
then:
2^4 = 16
then:
![\sqrt[4]{16} = 16^(1/4) = 2](https://img.qammunity.org/2022/formulas/mathematics/high-school/13okcoehylpdv2npx4uriw8z4sewi2zplx.png)
Now let's solve the problem:
