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Factor completely 8y^3 + 16y^2

2 Answers

2 votes


8y^3=8y^2(y)\\\\16y^2=8y^2(2)\\\\8y^3+16y^2=8y^2(y)+8y^2(2)=8y^2(y+2)

User Roger Willcocks
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5 votes

Answer:

8y^2 (y+2)

Explanation:

8y^3 + 16y^2

both terms contain an 8 and a y^2 so we can factor them out

8y^2 (y+2)

User Davidisdk
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5.5k points