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What is the value of x if a rectangle has a perimeter of 50, a length of x + 5, and width of 11?

What is the value of x if a rectangle has a perimeter of 50, a length of x + 5, and-example-1
User ARtoo
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2 Answers

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Answer: 9


Explanation:

2[(x+5)+11]=50

2[x+16]=50

2x+32=50

2x=18

x=9 There you go! So this is your answer. Your missing 'x' equals 9.

User Whd
by
8.5k points
2 votes

Answer:

x = 9

Explanation:

Perimeter = 2 * width + 2 * length

= 2*11 + 2(x + 5) = 50

2x + 10 + 22 = 50

2x = 50 - 10 - 22

2x = 18

x = 9

User Amcaplan
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8.7k points

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