Answer:
A. Empirical formula => SiCl₂I₂
B. Molecular formula = SiCl₂I₂
Step-by-step explanation:
From the question given above, the following data were:
Silicone (Si) = 7.962 %
Chlorine (Cl) = 20.10 %
Iodine (I) = 71.94 %
Molar mass of compound = 352.8 g/mol
Empirical formula =?
Molecular formula =?
A. Determination of the empirical formula of the compound.
Si = 7.962 %
Cl = 20.10 %
I = 71.94 %
Divide by their molar mass
Si = 7.962 / 28 = 0.284
Cl = 20.10 / 35.5 = 0.566
I = 71.94 / 127 = 0.566
Divide by the smallest
Si = 0.284 / 0.284 = 1
Cl = 0.566 / 0.284 = 2
I = 0.566 / 0.284 = 2
Empirical formula => SiCl₂I₂
B. Determination of the molecular formula of the compound.
Empirical formula => SiCl₂I₂
Molar mass of compound = 352.8 g/mol
Molecular formula =?
Molecular formula = [SiCl₂I₂]ₙ
[SiCl₂I₂]ₙ = 352.8
[28 + (2×35.5) + (2×127)]n = 352.8
[28 + 71 + 254]n = 352.8
353n = 352.8
Divide both side by 353
n = 352.8 / 353
n = 1
Molecular formula = [SiCl₂I₂]ₙ
Molecular formula = [SiCl₂I₂]₁
Molecular formula = SiCl₂I₂