Question

LiNO3(aq) and Na2CO3(aq).If a solid forms when solutions containing these salts are mixed, write the ionic equation.

Answer 1

The net ionic equation :

`2Li^+(aq)+CO_3^(2-)(aq)\rightarrow Li_2CO_3(s)`

Step-by-step explanation:

When aqueous solution of lithium nitrate and sodium carbonate are a=mixed together they give solid precipitate of lithium carbonate and aqueous solution of sodium nitrate.

`2LiNO_3(aq) +Na_2CO_3(aq)\rightarrow Li_2CO_3(s)+2NaNO_3(aq)`

When lithium nitrate in its aqueous solution gives lithium ions and carbonate ions.

`2LiNO_3(aq)\rightarrow 2Li^+(aq)+2NO_3^(-)(aq)`

When sodium carbonate in its aqueous solution gives lithium ions and carbonate ions.

`Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^(2-)(aq)`

When sodium nitrate in its aqueous solution gives lithium ions and carbonate ions.

`NaNO_3(aq)\rightarrow 2Na^+(aq)+NO_3^(-)(aq)`

`2Li^+(aq)+2NO_3^(-)(aq)+2Na^+(aq)+CO_3^(2-)(aq)\rightarrow Li_2CO_3(s)+2Na^+(aq)+2NO_3^(-)(aq)`

Cancelling out common ions i.e. spectators ions from both the sides, we get the net ionic equation :

`2Li^+(aq)+CO_3^(2-)(aq)\rightarrow Li_2CO_3(s)`

Answer 2

The ionic equation is as below

2Li + (aq) + CO₃²- → Li₂CO₃ (s)

explanation

step 1: write the molecular equation

2 LiNO₃ (aq) + Na₂CO₃ (aq) → Li₂CO₃ (s) +2NaNO₃

Step 2 : break the soluble electrolyte in ions

2 Li⁺ (aq) +2NO₃⁻(aq) + 2Na⁺(aq) + CO₃²⁻ (aq) → Li₂CO₃ + 2Na⁺(aq) +2NO₃⁻(aq)

cancel the spectator ion ( 2Na⁺ and 2No₃⁻)

The ionic equation is therefore

2Li⁺ (aq) + CO₃²⁻(aq) → Li₂CO₃ (s)