Question

If a vector's magnitude is 32 units right and 28 units up, what's the approximate magnitude of a vector that's one-fourth the length of the first vector?

Answer 1

10.6 units

Explanation:

First of all, let's find the magnitude of the first vector, which is given by the resultant of its two components:

`R=√(32^2+28^2)=42.5` units

The second vector has a length which is 1/4 of the length of the first vector, so it is

`R'=(1)/(4)R=(1)/(4)(42.5)=10.6` units