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Under ideal conditions a certain bacteria population is known to double every three hours. Suppose that there are initially 100 bacteria. Estimate the size of the population after 20 hours.

User Mad Myche
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4.8k points

2 Answers

8 votes

Answer:

The answer is "10159"

Explanation:

Every 3 hours the population doubles, with an initial population of 100.


\to P(t) = 100 * 2^{(t)/(3)}


P(t)= \text{The population of bacteria}\\\\ t = \text{time in hours} \\

when t=20


\to p(20)= 100 * 2^{(20)/(3)} \\


= 100 * 101.593667\\\\ =10159.3667

User Nikkiya
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4.9k points
6 votes

Answer:

the estimation of the size of the population after 20 hours is 10159

Explanation:

The computation of the size of the population after 20, hours is shown below;

= 100 2^(20 by 3)

= 10159.36

If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant

User Seryoga
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4.5k points