Answer
Find out the what is the perimeter of the rectangle .
To prove
As given
The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) .
As shown in the graph given below
Name the vertices A (−3, 4) , B(7, 2) , C(6, −3) , and D(−4, −1) .
Formula
![Distance\ formula = \sqrt{(x_(2) - x_(1))^(2) + (y_(2) - y_(1))^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/3pfucyz019yxt9mtbbhrxy29pu11ym586w.png)
Vertices are A (-3, 4) and B (7,2)
![AB = \sqrt{(7 - (-3))^(2) + (2 - 4)^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/ukoawlcjmep029g1uow61eq35av8p69qre.png)
![AB = \sqrt{(10)^(2) + (-2)^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/expipf5t734gf7b4bvqr5hre8pbez72d6u.png)
![AB = √(100 + 4)](https://img.qammunity.org/2019/formulas/mathematics/high-school/o8psdpbu2wp4sdlwf055o1kuyv9e5sk4iw.png)
![AB = √(104)](https://img.qammunity.org/2019/formulas/mathematics/high-school/qdgapb5f2es643ouqysh2wix7y53at9qxq.png)
AB = 10.2 units (approx)
As this is the rectangles
Thus AB = CD (The opposite sides of the rectangle are equal.)
CD = 10.2 units (approx)
Now vertices are B(7, 2) and C(6, −3)
![BC = \sqrt{(6 - 7)^(2) + (-3 -2 )^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/ljfvdcf4j90bidqn3t8trc6quu19au6b54.png)
![BC = \sqrt{(-1)^(2) + (-5 )^(2)}](https://img.qammunity.org/2019/formulas/mathematics/high-school/4euh8etmhmaqosrt81eevxm2dli05akavf.png)
![BC = √(26)](https://img.qammunity.org/2019/formulas/mathematics/high-school/c3v16i83smtr6vnj1t93jn5c610qj7b1oq.png)
BC = 5.1 units(Approx)
As this is the rectangles
Thus BC = AD (The opposite sides of the rectangle are equal.)
AD = 5.1 units
Formula
Perimeter of a rectangle = 2 (length + Breadth)
As length = 10.2 units
Breadth = 5.1 units
Put in the formula
Perimeter of a rectangle = 2 × (10.2 + 5.1)
= 2 × 15.3
= 30.6 units.
Therefore the perimeter of a rectangle is 30.6 units .