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A convex figure has three sides what is the sum of its exterior angles

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A convex figure with three sides is triangle. The sum of the measures of all interior angles of the triangle is 180°.

Let
\alpha, \beta, \gamma be interior angles of this triangle. Then


\alpha+\beta+\gamma=180^(\circ).

Find exterior angles of this triangle:

1.
180^(\circ)-\alpha is exterior angle adjacent to the interior angle
\alpha.

2.
180^(\circ)-\beta is exterior angle adjacent to the interior angle
\beta.

3.
180^(\circ)-\gamma is exterior angle adjacent to the interior angle
\gamma.

The sum of the measures of all exterior angles is


180^(\circ)-\alpha+180^(\circ)-\beta+180^(\circ)-\gamma=540^(\circ)-(\alpha+\beta+\gamma)=540^(\circ)-180^(\circ)=360^(\circ).

Answer: 360°

User RenatoSz
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