Question

Yanick and Nancy drive two identical 1380 kilogram cars at 30 m/sec. Yanick slams on the brakes and his car comes to a stop in 1.02 seconds. Nancy lightly applies the brakes and stops her car in 3.7 seconds. Calculate the stopping force for each car.

Answer 1

Yanick drive the car at initial speed of 30 m/s and slams the brakes and stop the car in 1.02 s

So here the acceleration of the car is given as

`a = (v_f - v_i)/(t)`

`a = (30 - 0)/(1.02)`

`a = 29.41 m/s^2`

now the force to stop the car is given as

`F = ma`

`F = 1380* 29.41 = 40588.2 N`

Nancy drive the car at initial speed of 30 m/s and slams the brakes and stop the car in 3.7 s

So here the acceleration of the car is given as

`a = (v_f - v_i)/(t)`

`a = (30 - 0)/(3.7)`

`a = 8.11 m/s^2`

now the force to stop the car is given as

`F = ma`

`F = 1380* 8.11 = 11189.2 N`