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In guinea pigs, smooth coat (S) is dominant over rough coat (s), and black coat (B) is dominant over white coat (b). In the cross SsBb × SsBb, how many of the offspring will have a smooth black coat, on average?

a. 1⁄4
b. about 9⁄16
c. 1⁄16
d. 6⁄16
e. 2⁄6

User Papanito
by
7.5k points

1 Answer

4 votes

Answer:

The correct answer is - b. about 9⁄16

Step-by-step explanation:

I the given question is given:

Smooth coat (S) is dominant over rough coat (s), and black coat (B) is dominant over white coat (b)

Then cross betwen SsBb × SsBb

gametes:

SB, Sb, sB, and sb for each parent:

SB Sb sB sb

SB SSBB SSBb SsBB SsBb

Sb SSBb SSbb SsBb Ssbb

sB SsBB SsBb SsBB ssBb

sb SsBb Ssbb ssBb ssbb

every offspring with SB in the combination will express a smooth black coat that is 9 according to the Punnett out of 16 offspring.

User Ananay Mital
by
9.0k points
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