Question

Cream of tartar, a common ingredient in cooking, is the common name for potassium bitartrate (abbreviated KBT, molar mass 188.2 g/mol). Historically, KBT was a crystalline solid that formed on the casks of wine barrels during the fermentation process. Calculate the maximum mass of KBT that can dissolve in 280. mL of solution to make a saturated solution. KBT dissolves to form the potassium ion (K+) and the bitartrate ion (abbreviated as BT-).

KBT(s) → K+(aq) + BT-(aq) Ksp = 3.8×10-4

Answer 1

To calculate the maximum mass of KBT that can dissolve in a given volume of solution, we can use the solubility product constant (Ksp) of KBT. By setting up an equation using the concentrations of the potassium ion and the bitartrate ion, we can solve for the maximum mass of KBT.

Step-by-step explanation:

To calculate the maximum mass of potassium bitartrate (KBT) that can dissolve in 280 mL of solution to make a saturated solution, we need to use the solubility product constant (Ksp) of KBT. The Ksp represents the equilibrium expression for the dissolution of KBT, and it is equal to the product of the concentrations of the potassium ion (K+) and the bitartrate ion (BT-). So, we can set up the equation:

Ksp = [K+][BT-]

Using the information given in the question, we can solve for the maximum mass of KBT that can dissolve by converting the volume of solution to liters and using the molar mass of KBT.

Answer 2

0.288g KBT can be dissolved

Step-by-step explanation:

The dissolution of KBT produce the dissociation in K⁺ and BT⁻ ions as follows:

KBT(s) → K+(aq) + BT-(aq) Ksp = 3.8×10-4

Where Ksp is defined as:

Ksp = 3.8x10⁻⁴ = [K⁺][BT⁻]

Thus, we need to find the concentration of KBT that can be dissolved = [K⁺] = [BT⁻]:

3.8x10⁻⁴ = [K⁺][BT⁻]

3.8x10⁻⁴ = [KBT][KBT]

3.8x10⁻⁴ = [KBT]²

0.01949M = [KBT]

In 280mL = 0.280L, the moles of KBT that can be dissolved are:

0.01949mol / L * 0.280L =

5.458x10⁻³ moles of KBT. In grams (Using molar mass):

5.458x10⁻³ moles of KBT * (188.2g/mol) =

0.288g KBT can be dissolved