Question

A pyramid has a square base with sides 8" and a slant height of 5". What is the area?

Answer 1

The answer is forty five

Answer 2

We can find the surface area of the pyramid as

`A = l*w+l*\sqrt{((w)/(2) )^(2) +h^(2) }+w*\sqrt{((l)/(2) )^(2) +h^(2)}`

here , because the base is squre so

`l = w = 8`

`h = 5`

By putting the values of l,w and h

we get

`A = 8*8+8*\sqrt{((8)/(2) )^(2) +5^(2) }+8*\sqrt{((8)/(2) )^(2) +5^(2)}`

`A = 64+8*√(16 +25 )+8*√(16 +25)`

`A = 64+(8*\sqrt{41) +(8*√(41))`

`A = 64+51.2+51.2`

`A = 166.4`