Answer:
The solution to the equation system given is:
Explanation:
First, we must know the equations given:
- 2x + 3y = 1
- 3x + y = 5
Following Crammer's Rule, we have the matrix form:
![\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] =\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]](https://img.qammunity.org/2022/formulas/mathematics/college/oqvo0zkkul61tpeeaihxsnqady78pdmuta.png)
Now we solve using the determinants:
![x=\frac{\left[\begin{array}{ccc}1&3\\5&1\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =((1*1)-(5*3))/((2*1)-(3*3)) = (1-15)/(2-9) =(-14)/(-7) = 2](https://img.qammunity.org/2022/formulas/mathematics/college/jw81m2vdbicc10c6h6lcns26d5sfxymc7z.png)
![y=\frac{\left[\begin{array}{ccc}2&1\\3&5\end{array}\right]}{\left[\begin{array}{ccc}2&3\\3&1\end{array}\right] } =((2*5)-(3*1))/((2*1)-(3*3))=(10-3)/(2-9) =(7)/(-7)=-1](https://img.qammunity.org/2022/formulas/mathematics/college/sy5tppjb2tz086swrys16e5o74ktmvf2gd.png)
Now, we can find the answer which is x= 2 and y= -1, we can replace these values in the equation to confirm the results are right, with the first equation:
- 2x + 3y = 1
- 2(2) + 3(-1)= 1
- 4 - 3 = 1
- 1 = 1
And, with the second equation:
- 3x + y = 5
- 3(2) + (-1) = 5
- 6 - 1 = 5
- 5 = 5