Question

A swift moving hawk is moving due west with a speed of 30 m/s; 5.0 s later it is moving due north with a speed of 20 m/s.

(A) What are the magnitude and direction of Δvav vector during this 5 s interval? and
(B) What are the magnitude and direction of vector aav during this 5 s interval?

Answer 1

See explanation

Step-by-step explanation:

Now we have;

vi = (-30, 0) m/s

vf = (0, 20) m/s

Δvav= vf - vi= (30, 20) m/s

magnitude of Δvav= √30^2 + 20^2 = 36.0 m/s

Direction = tan-1(20/30) = 33.69°

For aav

aav= Δvav/t = (30/5, 20/5) = (6,4) m/s^2

magnitude of aav = √6^2 + 4^2 = 7.2 m/s^2

direction of aav = tan-1(4/6) = 33.69°