Answer:
(s-t)(-1) = -1
(s+t)(-1) = -7
Explanation:
Given the following set of functions
s(x)=2x-2
t(x)=3x
(s-t)(x) = s(t) - t(x)
(s-t)(x) = 2x - 2 - 3x
(s-t)(x) = -x -2
(s-t)(-1) = -(-1) - 2
(s-t)(-1) = 1-2
(s-t)(-1) = -1
(s+t)(x) = s(t) + t(x)
(s+t)(x) = 2x - 2 + 3x
(s+t)(x) = 5x -2
(s+t)(-1) = 5(-1) - 2
(s+t)(-1) = -5-2
(s+t)(-1) = -7