Question

Guys please help this is a math question

Answer 1

81.5

Explanation:

<G and <H are congruent

<F and <I are congruent

so the last two angles in both triangles must also be congruent

this means that <K and <J are congruent

so we can create this equation: <K = <J

substitute the angles with what we know: 4
`y^(2)` = 6
`y^(2)` - 40

add 40 to both sides and subtract 4
`y^(2)` from both sides: 40 = 2
`y^(2)`

you get: 20 =
`y^(2)`

root square on both sides:
`√(20)` =
`\sqrt{y^(2) }`

you get: y ≈ 4.5

substitute this into one of the equations for a missing variable:

6
`y^(2)` -----> 6 (4.5 x 4.5) - 40

6 ( 20.25) - 40

121.5 - 40

81.5